本文实例讲述了Python实现获取前100组勾股数的方法。分享给大家供大家参考，具体如下：
本来想采用穷举试探的方式来做这个算法，后来发现还是有点麻烦。从网络上找来了一种求解方法如下：
当a为大于1的奇数2n+1时，b=2n^2+2n,c=2n^2+2n+1。实际上就是把a的平方数拆成两个连续自然数。
编写代码如下：
#!/usr/bin/python
for n in range(1,101):
a = 2 * n +1
b = 2 * (n** 2) + 2 * n
c = b + 1
# check theresult
if a ** 2 +b ** 2 == c ** 2:
print("a= %d, b = %d, c = %d" %(a,b,c))
程序执行结果：
a = 3, b = 4, c = 5 a = 5, b = 12, c = 13 a = 7, b = 24, c = 25 a = 9, b = 40, c = 41 a = 11, b = 60, c = 61 a = 13, b = 84, c = 85 a = 15, b = 112, c = 113 a = 17, b = 144, c = 145 a = 19, b = 180, c = 181 a = 21, b = 220, c = 221 a = 23, b = 264, c = 265 a = 25, b = 312, c = 313 a = 27, b = 364, c = 365 a = 29, b = 420, c = 421 a = 31, b = 480, c = 481 a = 33, b = 544, c = 545 a = 35, b = 612, c = 613 a = 37, b = 684, c = 685 a = 39, b = 760, c = 761 a = 41, b = 840, c = 841 a = 43, b = 924, c = 925 a = 45, b = 1012, c = 1013 a = 47, b = 1104, c = 1105 a = 49, b = 1200, c = 1201 a = 51, b = 1300, c = 1301 a = 53, b = 1404, c = 1405 a = 55, b = 1512, c = 1513 a = 57, b = 1624, c = 1625 a = 59, b = 1740, c = 1741 a = 61, b = 1860, c = 1861 a = 63, b = 1984, c = 1985 a = 65, b = 2112, c = 2113 a = 67, b = 2244, c = 2245 a = 69, b = 2380, c = 2381 a = 71, b = 2520, c = 2521 a = 73, b = 2664, c = 2665 a = 75, b = 2812, c = 2813 a = 77, b = 2964, c = 2965 a = 79, b = 3120, c = 3121 a = 81, b = 3280, c = 3281 a = 83, b = 3444, c = 3445 a = 85, b = 3612, c = 3613 a = 87, b = 3784, c = 3785 a = 89, b = 3960, c = 3961 a = 91, b = 4140, c = 4141 a = 93, b = 4324, c = 4325 a = 95, b = 4512, c = 4513 a = 97, b = 4704, c = 4705 a = 99, b = 4900, c = 4901 a = 101, b = 5100, c = 5101 a = 103, b = 5304, c = 5305 a = 105, b = 5512, c = 5513 a = 107, b = 5724, c = 5725 a = 109, b = 5940, c = 5941 a = 111, b = 6160, c = 6161 a = 113, b = 6384, c = 6385 a = 115, b = 6612, c = 6613 a = 117, b = 6844, c = 6845 a = 119, b = 7080, c = 7081 a = 121, b = 7320, c = 7321 a = 123, b = 7564, c = 7565 a = 125, b = 7812, c = 7813 a = 127, b = 8064, c = 8065 a = 129, b = 8320, c = 8321 a = 131, b = 8580, c = 8581 a = 133, b = 8844, c = 8845 a = 135, b = 9112, c = 9113 a = 137, b = 9384, c = 9385 a = 139, b = 9660, c = 9661 a = 141, b = 9940, c = 9941 a = 143, b = 10224, c = 10225 a = 145, b = 10512, c = 10513 a = 147, b = 10804, c = 10805 a = 149, b = 11100, c = 11101 a = 151, b = 11400, c = 11401 a = 153, b = 11704, c = 11705 a = 155, b = 12012, c = 12013 a = 157, b = 12324, c = 12325 a = 159, b = 12640, c = 12641 a = 161, b = 12960, c = 12961 a = 163, b = 13284, c = 13285 a = 165, b = 13612, c = 13613 a = 167, b = 13944, c = 13945 a = 169, b = 14280, c = 14281 a = 171, b = 14620, c = 14621 a = 173, b = 14964, c = 14965 a = 175, b = 15312, c = 15313 a = 177, b = 15664, c = 15665 a = 179, b = 16020, c = 16021 a = 181, b = 16380, c = 16381 a = 183, b = 16744, c = 16745 a = 185, b = 17112, c = 17113 a = 187, b = 17484, c = 17485 a = 189, b = 17860, c = 17861 a = 191, b = 18240, c = 18241 a = 193, b = 18624, c = 18625 a = 195, b = 19012, c = 19013 a = 197, b = 19404, c = 19405 a = 199, b = 19800, c = 19801 a = 201, b = 20200, c = 20201
由于程序中加入了是否为勾股数的判断，因此这个清单应该是准确的。这个小题目求解下来，我自己的感觉是做事的方法中算法还是至关重要的！